Perl question: array member of referenced hash

[Shachar Shemesh]

Dov Grobgeld wrote:
> Noam beat me to it, but here's perl solution without additional variables:
>
> #!/usr/bin/perl
>
> %hash = (a=>['moo','goo','woo'],
>          foo=>3,
>          baz=>5);
>
> $ref = \%hash;
> foreach my $elem (@{$ref->{a}})
Hi Dov,

Yes, it works. Now can you, please, explain to me why? What is the role 
of each bracket you used (and its location)?

Shachar

-- 
Shachar Shemesh
Lingnu Open Source Consulting Ltd.
http://www.lingnu.com

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