Python on Ubuntu 18.04.6 LTS

[אורי]

I apologize about the subject. Feel free to change it. The main post was
about almost crashing my computer with the command  _py -c
"print(2**64**3)".
אורי
uri at speedy.net


On Tue, Jan 4, 2022 at 8:01 AM Michael Shiloh <michaelshiloh1010 at gmail.com>
wrote:

> Interesting discussion, but the subject seems quite wrong.
>
> ‪On Tue, Jan 4, 2022 at 9:32 AM ‫אורי‬‎ <uri at speedy.net> wrote:‬
>
>> From checking also powers of 3, I can't find more than c==5 (for 3**20
>> and 3**124).
>>
>> אורי
>> uri at speedy.net
>>
>>
>> ‪On Tue, Jan 4, 2022 at 7:24 AM ‫אורי‬‎ <uri at speedy.net> wrote:‬
>>
>>> Thank you, that's interesting. So all such numbers are divisible by 9. I
>>> didn't think about it.
>>>
>>> You might be interested in my related question:
>>>
>>> https://math.stackexchange.com/questions/4348279/what-is-the-highest-number-of-digits-so-that-this-number-of-digits-in-a-specific
>>>
>>> From checking about the first 50,000 powers of 2, I didn't find c more
>>> than 5, who actually appears only twice (c is the number of digits who
>>> appear exactly 10% of the time in the decimal form of a specific power of
>>> 2).
>>>
>>> אורי
>>> uri at speedy.net
>>>
>>>
>>> On Tue, Jan 4, 2022 at 6:53 AM Daniel Shahaf <d.s at daniel.shahaf.name>
>>> wrote:
>>>
>>>> אורי wrote on Tue, 04 Jan 2022 04:07 +00:00:
>>>> > Are there powers of 2 which give exactly 10% of each of the digits 0
>>>> to 9 (in
>>>> > decimal form)?
>>>>
>>>> No, because then the sum of the digits would be a multiple of nine, so
>>>> the
>>>> number wouldn't be a power of two.
>>>>
>>> _______________________________________________
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>>
>
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